Question 990006: The second of three numbers is one less than the first. The third number is five less than twice the second. If the third number exceeds the first number by 12, find the three numbers
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! let the three number be a, b, c
:
write an equation for each statement
:
The second of three numbers is one less than the first.
b = a - 1
The third number is five less than twice the second.
c = 2b - 5
If the third number exceeds the first number by 12,
c = a + 12
:
find the three numbers
In the 2nd equation, replace c with (a+12)
a + 12 = 2b - 5
a - b = -5 - 12
a - 2b = -17
replace b with (a-1)
a - 2(a-1) = -17
a - 2a + 2 = -17
a - 2a = -17 - 2
-a = -19
a = 19
find
b = 19 - 1
b = 18
find c
c = 19 + 12
c = 31
:
The three number: 19, 18, 31
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