SOLUTION: For what value of m will the triangle formed by the lines y=5, y=mx-6 and y=-mx-6 be equilateral?

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Question 989964: For what value of m will the triangle formed by the lines y=5, y=mx-6 and
y=-mx-6 be equilateral?
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
The two lines have y-intercepts equal to -6.
So the altitude of the equilateral triangle is A=5-%28-6%29=11
The altitude, half side, and side form a right triangle.
A%5E2%2B%28S%2F2%29%5E2=S%5E2
A%5E2=%283%2F4%29S%5E2
A=%28sqrt%283%29%2F2%29S
11=%28sqrt%283%29%2F2%29S
S=22%2Fsqrt%283%29
The top edge is centered about x=0 so the endpoints of the two vertices are
(11%2Fsqrt%283%29,5) and (-11%2Fsqrt%283%29,5).
Now that you have two points, find the slope.
m=%285-%28-6%29%29%2F%2811%2Fsqrt%283%29-0%29
m=11%2F%2811%2Fsqrt%283%29%29
m=sqrt%283%29
.