SOLUTION: how many gal. of a 90% sugar solution must be mixed with 3 gal. of a 60% sugar solution to make a 81% solution

Algebra ->  Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: how many gal. of a 90% sugar solution must be mixed with 3 gal. of a 60% sugar solution to make a 81% solution      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 989908: how many gal. of a 90% sugar solution must be mixed with 3 gal. of a 60% sugar solution to make a 81% solution
Answer by macston(5194) About Me  (Show Source):
You can put this solution on YOUR website!
.
N=amount of 90% solution.
.
0.60(3 gal)+0.90(N)=0.81(N+3)
1.8gal+0.90N=0.81N+2.43gal
0.09N=0.63gal
N=7gal
.
ANSWER You should mix 7 gallons of 90% solution with 3 gallons
of 60% solution to get 10 gallons of 81% solution.
.
CHECK:
0.60(3gal)+0.90(7gal)=0.81(10gal)
1.8gal+6.3gal=8.1gal
8.1gal=8.1gal