SOLUTION: How much square feet of surface area is in a cylinder 48' high and 80' diameter

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Question 98977: How much square feet of surface area is in a cylinder 48' high and 80' diameter
Found 2 solutions by jim_thompson5910, checkley71:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Since the diameter is 80', the radius is 40' (which is half of the diameter)


Solved by pluggable solver: Surface area and Volume of a cylinder
The surface area (SA) of a cylinder, excluding the base area and top area, is given by
SA+=+2%2Api%2AR%2AH

When the areas of base and top are included, the surface area becomes
SA+=+2%2Api%2AR%2AH+%2B+2%2Api%2AR%5E2
SA+=+2%2Api%2AR%2A%28R%2BH%29

The volume of the cone can be found by the formula
V+=+pi%2AR%5E2%2AH


In our case the desired values are thus:

SA (without base and top) = 2%2Api%2A40%2A48+=+12063.715776
SA (with base and top) = 2%2Api%2A40%2A48+%2B+2%2Api%2A40%5E2+=+22116.812256
V = pi%2A40%5E2%2A48+=+241274.31552


For more on this topic, refer to Surface area and Volume.

Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
TSA=(PI*D)H+2(PI*R^2)
TSA=3.14*80+2(3.14*40^2)
TSA=2512+2*5024
TSA=2512+10048
TSA=12560 IS THE TOTAL SURFACE AREA OF THIS CYLINDER.