SOLUTION: 390 worth of $10 and $20.If there were 3 more 10 bills than find the number of each denomination

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Question 989714: 390 worth of $10 and $20.If there were 3 more 10 bills than find the number of each denomination
Answer by macston(5194) About Me  (Show Source):
You can put this solution on YOUR website!
x=number of $10 bills; y=number of $20 bills=x-3
$10x+$20y=$390
$10x+$20(x-3)=$390
$10x+$20x-$60=$390
$30x=$450
x=15 ANSWER 1: There were fifteen $10 bills.
y=x-3=15-3=12 ANSWER 2: There were twelve $20 bills.
.
CHECK:
$10x+$20y=$390
$10(15)+$20(12)=$390
$150+$240=$390
$390=$390