SOLUTION: Arctan(1) + Arcsin(0) + Arccos{{{(sqrt(3)/2)}}}

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Question 9897: Arctan(1) + Arcsin(0) + Arccos%28sqrt%283%29%2F2%29
Answer by Edwin McCravy(20054) About Me  (Show Source):
You can put this solution on YOUR website!
Arctan(1) + Arcsin(0) + Arccos%28sqrt%283%29%2F2%29

Arctan(1) = ? asks tan(?) = 1 ---> answer: 45° or pi%2F4 radians

Arcsin(0) = ? asks sin(?) = 0 ---> answer: 0°  or 0 radians

Arccos%28sqrt%283%29%2F2%29 = ? asks cos(?) = sqrt%283%29%2F2 ---> answer: 30° or pi%2F6 radians

So, if your answer is to be in degrees:

Arctan(1) + Arcsin(0) + Arccos%28sqrt%283%29%2F2%29 = 45° + 0° + 30° = 75°    

Or if your answer is to be in radians:

Arctan(1) + Arcsin(0) + Arccos%28sqrt%283%29%2F2%29 = pi%2F4 + %220%22 + pi%2F6 = pi%2F4 + pi%2F6 = 3pi%2F12 + 2pi%2F12 = 5pi%2F12

Edwin