SOLUTION: Let y = {{{ 3x^4 - 5 }}} Find A,B, and C so that {{{ (dy)/(dx) = Ax^B + C }}} A = ____ B = ____ Then find the value of the derivative at 0. {{{ (dy)/(dx)}}}_| ___________

Algebra ->  Equations -> SOLUTION: Let y = {{{ 3x^4 - 5 }}} Find A,B, and C so that {{{ (dy)/(dx) = Ax^B + C }}} A = ____ B = ____ Then find the value of the derivative at 0. {{{ (dy)/(dx)}}}_| ___________      Log On


   

Question 989587: Let y = +3x%5E4+-+5+
Find A,B, and C so that +%28dy%29%2F%28dx%29+=+Ax%5EB+%2B+C+
A = ____
B = ____
Then find the value of the derivative at 0.
+%28dy%29%2F%28dx%29_|
_____________|............=____
_____________|x=0
Please explain
Thank you
Found 2 solutions by jim_thompson5910, Alan3354:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
y = 3x^4 - 5

y = 3x^4 - 5x^0

dy/dx = 4*3*x^(4-3) - 0*5*x^(0-1) ... use the power rule to find the derivative

dy/dx = 12x^2 - 0

dy/dx = 12x^2

So, A = 12, B = 2, C = 0

-------------------------------------------------------

Now plug in x = 0 into the dy/dx equation.

dy/dx = 12x^2

dy/dx = 12*0^2

dy/dx = 0

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Let y = 3x^4 + 5
------------------
dy/dx = 12x^3
---------------
A = 12
B = 3
C = 0
-----------------
Find A,B, and C so that
Then find the value of the derivative at 0.
-----------
dy/dx @ x = 0 = zero