SOLUTION: A grocer mixed pecans that cost $5.00/ kg with walnuts that cost 5.80/kg to create a 40 kg mixture how many kilograms of pecans are needed if blend is worth 5.50/kg? I tried m

Algebra ->  Linear-equations -> SOLUTION: A grocer mixed pecans that cost $5.00/ kg with walnuts that cost 5.80/kg to create a 40 kg mixture how many kilograms of pecans are needed if blend is worth 5.50/kg? I tried m      Log On


   

Question 989409: A grocer mixed pecans that cost $5.00/ kg with walnuts that cost 5.80/kg to create a 40 kg mixture how many kilograms of pecans are needed if blend is worth 5.50/kg?

I tried multiplying the 3 and dividing by 5.50 but I'm not really sure how to solve please help?
Answer by josgarithmetic(39615) About Me  (Show Source):
You can put this solution on YOUR website!
p quantity of pecan
w quantity of walnuts
p+w=40
w=40-p.

Try this using ONE variable.
%285p%2B5.8%2840-p%29%29%2F40=5.5
and solve for p.

Here is a video using the same idea but a different EXAMPLE:
two part mixture for price using one single variable