SOLUTION: Help please. -3a+6(a-2b)+a-7(a-2b)=pa+sb where p and s are integers find the value of (2p-4s). Thanks for your help.

Algebra ->  Equations -> SOLUTION: Help please. -3a+6(a-2b)+a-7(a-2b)=pa+sb where p and s are integers find the value of (2p-4s). Thanks for your help.      Log On


   



Question 989031: Help please. -3a+6(a-2b)+a-7(a-2b)=pa+sb where p and s are integers find the value of (2p-4s). Thanks for your help.
Found 2 solutions by stanbon, macston:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
-3a+6(a-2b)+a-7(a-2b)=pa+sb where p and s are integers find the value of (2p-4s). Thanks for your help.
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-3a+a-7a -12b + 14b = pa + sb
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-9a + 2b = pa + sb
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p = -9
s = 2
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Ans: 2p-4s = -18-8 = -26
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Cheers,
Stan H.
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Answer by macston(5194) About Me  (Show Source):
You can put this solution on YOUR website!
.
-3a+6(a-2b)+a-7(a-2b)=pa+sb
-3a+6a-12b+a-7a+14b=pa+sb
-3a+2b=pa+sb
p=-3, s=2
.
2p-4s=2(-3)-4(2)=-6-8=-14