SOLUTION: Draw the graph of a function p that fits the following description: p has a domain of all real numbers and a range of -2<y&#8804;5, p(-1)=p(4), and p is discontinuous at x=2.

Algebra ->  Graphs -> SOLUTION: Draw the graph of a function p that fits the following description: p has a domain of all real numbers and a range of -2<y&#8804;5, p(-1)=p(4), and p is discontinuous at x=2.      Log On


   



Question 988860: Draw the graph of a function p that fits the following description: p has a domain of all real numbers and a range of -2
Found 2 solutions by solver91311, Edwin McCravy:
Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


If the range is a single number, then every ordered pair in the set of ordered pairs that is the graph of the function must have exactly the same -coordinate. Since the domain is all real numbers, we now have the set of all ordered pairs (x,y) such that x is any real number and y = -2.

So what function describes this set of ordered pairs?

John

My calculator said it, I believe it, that settles it

Answer by Edwin McCravy(20056) About Me  (Show Source):
You can put this solution on YOUR website!
The other tutor thought you only said "a range of -2" because you used < without
skipping a space after it.  Of course you did not know not to do that.  This
site uses HTML and when you type anything after the symbol < without skipping a
space after it, the HTML thinks it's an HTML tag and doesn't print it. So
hereafter, if you submit a problem that involves the symbol " < ", always skip a
space after it, so what comes after it will not be deleted. 

I looked to see what you had typed and was able to answer your question.
What you typed was this:
Draw the graph of a function p that fits the following description: p has a domain of
all real numbers and a range of -2< y ≤ 5, p(-1)=p(4), and p is discontinuous at x=2.
This would be a piecewise function.  Here is an equation of such a function:



You weren't asked for the equation but only the graph.  But this is the
equation for such a function p(x)

Here's its graph, and its explanation below the graph:



Notice that its domain is all real numbers, because there is no value of
x for which we cannot find a value for p(x).  Notice that the graph approaches
the green line y = -2 on the left as a horizontal asymptote, which means the
graph never quite gets as low as -2 but it does reach 5 at x=0, so its range is
-2 < y ≤ 5.  The graph goes only as high as 5 and not as low as -2. 

Notice that it is discontinuous at x=2.  It does not include the point where the
open circle is drawn but it "jumps" up to the point (2,1.5) where there is a
closed circle.  Notice that there are also points marked at (-1,1.5) and (4,1.5)
which shows that p(-1) = p(4) = 1.5.

So this graph meets all your requirements.

Edwin