SOLUTION: Determine the equation of the straight line through the points (-2;1) and (3;-2)

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Question 988848: Determine the equation of the straight line through the points (-2;1) and (3;-2)
Answer by Shai(25) About Me  (Show Source):
You can put this solution on YOUR website!
Given A(-2,1) B(3,-2)
Slope=(y2-y1)/(x2-x1)
Slope=(-2-1)/((3-(-2))
Let us represent the slope here as m
Thus the equation of the line is
m(x-x1)=(y-y1)
Henceforth,
(-3/5)(x+2)=(y-1)
Thus the equation of the line is
3x+5y+1=0