SOLUTION: The fourth term of a geometric progression exceeds the third term by 54, and the sum of the second and third term is 36. Find the common ratio if it is positive

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Question 988607: The fourth term of a geometric progression exceeds the third term by 54, and the sum of the second and third term is 36. Find the common ratio if it is positive
Found 3 solutions by MathLover1, KMST, MathTherapy:
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
if the fourth term a%5B4%5D exceeds the third term a%5B3%5D by 54, we have
a%5B4%5D-a%5B3%5D+=54....eq.1
if the sum of the second a%5B2%5Dand third term a%5B3%5D is 36, we have
a%5B2%5D%2Ba%5B3%5D=36....eq.2
By using a%5Bn%5D=a%5B1%5D%2Ar%5E%28n-1%29 we have:

a%5B1%5D%2Ar%5E3-a%5B1%5D%2Ar%5E2=54....eq.1
a%5B1%5D%2Ar%2Ba%5B1%5D%2Ar%5E2=36....eq.2
---------------------------------------------------add eq.2 and eq.1

a%5B1%5D%2Ar%5E3-a%5B1%5D%2Ar%5E2%2Ba%5B1%5D%2Ar%2Ba%5B1%5D%2Ar%5E2=54%2B36
a%5B1%5D%2Ar%5E3%2Ba%5B1%5D%2Ar=90
a%5B1%5D%28r%5E3%2Br%29=90
a%5B1%5D=90%2F%28r%5E3%2Br%29.............substitute in eq.2

90%2F%28r%5E3%2Br%29%2Ar%2B90%2F%28r%5E3%2Br%29%2Ar%5E2=36....eq.2
90r%2F%28r%5E3%2Br%29%2B90r%5E2%2F%28r%5E3%2Br%29=36
%2890r%2B190r%5E2%29=36%28r%5E3%2Br%29
90r%281%2Br%29=36r%28r%5E2%2B1%29......divide by 18
5%281%2Br%29=2%28r%5E2%2B1%29
5%2B5r=2r%5E2%2B2
2r%5E2%2B2-5r-5=0
2r%5E2-5r-3=0
%28r-3%29+%282+r%2B1%29+=+0
=> one solution will be: %28r-3%29+=+0=> highlight%28r=3%29
=> another solution will be: 2r%2B1=0=>2r=-1=>highlight%28r=-1%2F2%29
now we can find first term:
if highlight%28r=3%29
a%5B1%5D%2A%283%29%2Ba%5B1%5D%2A%283%29%5E2=36....eq.2
3a%5B1%5D%2B9a%5B1%5D=36
12a%5B1%5D=36
highlight%28a%5B1%5D=3%29

if highlight%28r=-1%2F2%29:
a%5B1%5D%2A%28-1%2F2%29%2Ba%5B1%5D%2A%28-1%2F2%29%5E2=36....eq.2
a%5B1%5D%2A%28-1%2F2%29%2Ba%5B1%5D%2A%281%2F4%29=36......multiply by 4
-2a%5B1%5D%2Ba%5B1%5D=144
-a%5B1%5D=144
highlight%28a%5B1%5D=+-144%29

so, there are two solutions:
1. highlight%28a%5B1%5D=+3%29 and highlight%28r=3%29
2.highlight%28a%5B1%5D=+-144%29 and highlight%28r=-1%2F2%29


then the second term is:
if a%5B1%5D=+3 and r=3:
a%5B2%5D=3%2A3
a%5B2%5D=9
third term is
a%5B3%5D=3%2A3%5E2
a%5B3%5D=27
fourth term
a%5B4%5D=3%2A3%5E3
a%5B4%5D=3%2A27
a%5B4%5D=81
the terms of sequence are:=>3%2C9%2C27%2C81


if a=-144,r=-1%2F2
a%5B2%5D=+-144%2A%28-1%2F2%29%5E1
a%5B2%5D=-144%2F-2
a%5B2%5D=72.
third term is
a%5B3%5D=-144%2A%28-1%2F2%29%5E2
a%5B3%5D=+-144%281%2F4%29
a%5B3%5D=+-36
and fourth term is
a%5B4%5D=+-144%2A%28-1%2F2%29%5E3
a%5B4%5D=+-144%28-1%2F8%29
a%5B4%5D=18
the terms of sequence are:=>-144%2C72%2C-36%2C18

now, check given data:
for =>3%2C9%2C27%2C81
a%5B4%5D=a%5B3%5D+%2B54....eq.1
81=27+%2B54
81=81
a%5B2%5D%2Ba%5B3%5D=36....eq.2
9%2B27=36
36=36

for =>-144%2C72%2C-36%2C18
a%5B4%5D=a%5B3%5D+%2B54....eq.1
18=-36+%2B54
18=18
a%5B2%5D%2Ba%5B3%5D=36....eq.2
72%2B%28-36%29=36
36=36


Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
r= the common ratio.
a%5B2%5D= the second term.
a%5B3%5D=a%5B2%5D%2Ar= the third term.
a%5B3%5D=a%5B3%5D%2Ar=a%5B2%5D%2Ar%5E2= the fourth term.
The fourth term of a geometric progression exceeds the third term by 54 translates as
a%5B4%5D-a%5B3%5D=54<-->a%5B2%5D%2Ar%5E2-a%5B2%5D%2Ar=54<-->a%5B2%5D%2A%28r%5E2-r%29=54 .
The sum of the second and third term is 36 translates as
a%5B2%5D%2Ba%5B3%5D=36<-->a%5B2%5D%2Ba%5B2%5D%2Ar=36<-->a%5B2%5D%2A%281%2Br%29=36 .
The ratio both equations tells us that
%28a%5B2%5D%2A%28r%5E2-r%29%29%2F%28a%5B2%5D%2A%281%2Br%29%29=54%2F36-->%28r%5E2-r%29%2F%281%2Br%29=3%2F2-->2%28r%5E2-r%29=3%281%2Br%29-->2r%5E2-2r%29=3%2B3r}-->2r%5E2-5r-3=0 .
The equation 2r%5E2-5r-3=0 is a quadratic equation.
As is true for all quadratic equations, it can be solved by "completing the square, or by using the quadratic formula.
This particular quadratic equation can also be solved by factoring:
2r%5E2-5r-3=0--->2r%5E2-6r%2Br-3=0--->2r%28r-3%29%2Br-3=0}--->%282r%2B1%29%28r-3%29=0--->system%28highlight%28r=3%29%2C%22or%22%2Cr=-1%2F2%29 .
If the common ratio is positive, it must be highlight%28r=3%29 .

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!
The fourth term of a geometric progression exceeds the third term by 54, and the sum of the second and third term is 36. Find the common ratio if it is positive
Since a%5B1%5D+=+a%5B1%5D, then a%5B2%5D+=+a%5B1%5Dr, a%5B3%5D+=+a%5B1%5Dr%5E2, and a%5B4%5D+=+a%5B1%5Dr%5E3

Since a%5B4%5D exceeds a%5B3%5D by 54, then we can say that: a%5B1%5Dr%5E3+-+a%5B1%5Dr%5E2+=+54
a%5B1%5D%28r%5E3+-+r%5E2%29+=+54
a%5B1%5D+=+54%2F%28r%5E3+-+r%5E2%29 ---------- eq (i)
Since the sum of a%5B2%5D and a%5B3%5D is 36, then we can say that: a%5B1%5Dr+%2B+a%5B1%5Dr%5E2+=+36
a%5B1%5D%28r+%2B+r%5E2%29+=+36
a%5B1%5D+=+36%2F%28r+%2B+r%5E2%29 --------- eq (ii)
Since a%5B1%5D+=+54%2F%28r%5E3+-+r%5E2%29 and a%5B1%5D+=+36%2F%28r+%2B+r%5E2%29, we can then say that: 54%2F%28r%5E3+-+r%5E2%29+=+36%2F%28r+%2B+r%5E2%29
54%28r+%2B+r%5E2%29+=+36%28r%5E3+-+r%5E2%29 ------ Cross-multiplying
3%28r+%2B+r%5E2%29+=+2%28r%5E3+-+r%5E2%29 -------- Factoring out GCF, 18
3r+%2B+3r%5E2+=+2r%5E3+-+2r%5E2
2r%5E3+-+2r%5E2+-+3r%5E2+-+3r+=+0
2r%5E3+-+5r%5E2+-+3r+=+0
r%282r%5E2+-+5r+-+3%29+=+r%280%29
2r%5E2+-+5r+-+3+=+0
(r - 3)(2r + 1) = 0
Common ratio, or highlight_green%28r+=+3%29 OR r+=+-+1%2F2 (ignore, since r MUST be > 0)