SOLUTION: There is a collection of nickels, dimes, and quarters with total value of $47.60. There are 28 more dimes than nickels. There are 5 times as many quarters as dimes. How many quarte

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: There is a collection of nickels, dimes, and quarters with total value of $47.60. There are 28 more dimes than nickels. There are 5 times as many quarters as dimes. How many quarte      Log On


   

Question 988547: There is a collection of nickels, dimes, and quarters with total value of $47.60. There are 28 more dimes than nickels. There are 5 times as many quarters as dimes. How many quarters are in the collection?
Answer by CubeyThePenguin(3113) About Me  (Show Source):
You can put this solution on YOUR website!
n = number of nickels
d = number of dimes
q = number of quarters

5n + 10d + 25q = 4760
d = n + 28
q = 5d = 5(n + 28)

Write everything in terms of n.

5n + 10d + 25q = 4760
5n + 10(n + 28) + 25(5(n+28)) = 4760
5n + 10n + 280 + 125n + 3500 = 4760
140n = 980
n = 7

There are 7 nickels, 35 dimes, and 175 quarters in the collection.