SOLUTION: Charls and David agreed to meet in Chicago for the weekend. Charls' travel 205 miles in the same time David travels 190 miles. If Charls rate of travel is 3 mph tha

Algebra ->  Rational-functions -> SOLUTION: Charls and David agreed to meet in Chicago for the weekend. Charls' travel 205 miles in the same time David travels 190 miles. If Charls rate of travel is 3 mph tha      Log On


   

Question 988535: Charls and David agreed to meet in Chicago for the weekend. Charls' travel 205 miles in the same time David travels 190 miles. If Charls rate of travel is 3 mph than David's and they travel the same lenght of time, at what speed does Charls travel?
Answer by macston(5194) About Me  (Show Source):
You can put this solution on YOUR website!
.
x=Charles' rate of speed
Assuming Charles is 3mph faster than David
.
Since times are the same:
205mi/x=190/x-3 Cross multiply.
205mi(x-3mph)=190mi(x)
205mi(x)-615mi^/hr=190mi(x)
15mi(x)=615mi^2/hr
x=41mph
ANSWER: Charles traveled at 41 mph.