SOLUTION: How much 20% acid solution and how much 35% acid solution should be used to fill an order for 25 liters of a 26% acid solutions

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Question 988413: How much 20% acid solution and how much 35% acid solution should be used to fill an order for 25 liters of a 26% acid solutions
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
x=20% acid
25-x=35% acid
.20x+(0.35)(25-x)=0.25*26
.20x+8.75-.35x=6.50
-0.15x=-2.25
x=15 liters of 20% acid
25-x=10 liters of 35% acid.
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Pure acid
15*0.20+10(.35)=3+3.5=6.5
25*.26=6.5 check