Question 98824:  The length of a a rectangle is twice as long as the width. The perimeter of the rectangle is 72 in. What are the length and width of this rectangle. 
 Found 2 solutions by  doukungfoo, anjali_yamini: Answer by doukungfoo(195)      (Show Source): 
You can  put this solution on YOUR website! Ok first lets make some statements about a rectangle. 
The perimeter of a rectangle is equal to the sum of all its sides. 
Both sides that make up a rectangles length will always be equal 
and both sides that make up a reactangles width will always be equal. 
Now we can write and equation to express the perimeter of the rectangle, but first lets define some variables. length = a and width = b The perimeter is given to be 72 inches. So since we know the perimeter of a rectangle is equal to the sum of all its sides we can say that: 
a + a + b + b = 72 
then simplify it to 
2a + 2b = 72 
Now the problem also tells us that the length is equal to twice the width. That can be expressed as: 
a = 2b 
Now since length = a and a = 2b we can replace the a in 2a + 2b = 72 with 2b 
so now you have this: 
2(2b) + 2b = 72 
Since there is now only one variable we can solve the equation for b 
first multiply 2 times 2b 
4b + 2b = 72 
then combine like terms 
6b = 72 
now divide both sides of the equal sign by 6 
6b/6 = 72/6 
b = 12 
Now that we have solve for b we can plug that value into our original equation 
2a + 2b = 72 
replace b with 12 
2a + 2(12) = 72 
multiply 2 times 12 
2a + 24 = 72 
subtract 24 from both sides of equal sign 
2a = 48 
divide both sides of equal sign by 2 
a = 24 
to check plug both answers into original equation. 
also don't forget the answers are in the unit of inches because the perimeter was given as 72 inches. 
 Answer by anjali_yamini(27)      (Show Source): 
You can  put this solution on YOUR website!      
 
let : 
  l= length of the rectangle 
  w = width of rectangle  
  p = perimeter of rectangle = 72 
 
 
  we know that  perimeter = sum of all the sides  
                so, p = l+l+w+w =2(l+w)
 
                since length is twice the width, 
                    l= 2w 
                so, p = 2(2w +w)
 
                  so, 72 = 2( 3w) 
                   so, 72/2 = 3w 
                    so, 36 = 3w 
                     so, 36/3 = w 
                      so, 12 =w
 
                so l = 2*12 = 24
 
   thus the length of the rectangle is 24in, and the width is 12in.
 
check :
 
  p = 2(l+w) 
   p = 2(12 +24) 
   p = 2 * 36 
   p = 72 
    
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