SOLUTION: paul finishes 3/10 of a work in 6 days and then finishes the remaining work the assistance of peter in 6 days. in what time can peter alone finish the same work?

Algebra ->  Rate-of-work-word-problems -> SOLUTION: paul finishes 3/10 of a work in 6 days and then finishes the remaining work the assistance of peter in 6 days. in what time can peter alone finish the same work?      Log On


   

Question 988236: paul finishes 3/10 of a work in 6 days and then finishes the remaining work the assistance of peter in 6 days. in what time can peter alone finish the same work?
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
Peter does one job alone in x days for a rate 1%2Fx.
Uniform Work Rates Rule RT=J to relate rate, time, amount of work or job.

Paul's rate is 3%2F10 job in 6days for a rate %283%2F10%29%2F6=3%2F%2810%2A6%29=1%2F20.

Work of Paul + work of Peter AND Paul = 1 whole job
3%2F10%2B%281%2F20%2B1%2Fx%29%2A6=1
Multiply members of the equation by 20x to eliminate the denominators as the first steps.

x=15