SOLUTION: Express without absolute value symbols |x+5|+|x-3| if -5 < x < 3
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Question 988227
:
Express without absolute value symbols
|x+5|+|x-3|
if -5 < x < 3
Answer by
CubeyThePenguin(3113)
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-5 < x < 3
|x + 5| = x + 5
|x - 3| = 3 - x
(x + 5) + (3 - x) = 8