SOLUTION: solve for x. 2^(2sinx)+2^(sinx)-6=0

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Question 988102: solve for x. 2^(2sinx)+2^(sinx)-6=0
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Use a substitution,
u=2%5E%28sin%28x%29%29
u%5E2=2%5E%282sin%28x%29%29
So then,
u%5E2%2Bu-6=0
%28u%2B3%29%28u-2%29=0
Two "u" solutions:
u%2B3=0
u=-3
2%5E%28sin%28x%29%29=-3
Not a possible solution in x.
,
,
u-2=0
u=2
2%5E%28sin%28x%29%29=2
sin%28x%29=1
highlight%28x=pi%2F2+%2B+%282pi%29%2Ak%29 where k is an integer.