SOLUTION: The radiator is in a car is filled with a solution of 60% antifreeze and 40% water. The manufacturer of the antifreeze suggests that for summer driving, optimal cooling if the oxyg

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Question 987975: The radiator is in a car is filled with a solution of 60% antifreeze and 40% water. The manufacturer of the antifreeze suggests that for summer driving, optimal cooling if the oxygen is obtained with only 50% antifreeze. If the capacity of the radiator is 3.6 L, how much coolant should be drained and replaced with water to reduce the antifreeze concentration to the recommended level?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
+.6%2A3.6+=+2.16+ liters of antifreeze
in radiator to begin with
-------------------------
Let +x+ = liters of coolant to be
drained and replaced with water
--------------------------------
+.6x+ = liters of antifreeze in the
coolant that is drained off
------------------------
In words:
[ liters of antifreeze I end up with ] / [ capacity of radiator ] = 50%
+%28+2.16+-+.6x+%29+%2F+2.16+=+.5+
+2.16+-+.6x+=+.5%2A2.16+
+.6x+=+.5%2A2.16+
+.6x+=+1.08+
+x+=+1.8+
1.8 liters of coolant should be
drained and replaced with water
------------------------------
check:
+%28+2.16+-+.6%2A1.8+%29+%2F+2.16+=+.5+
+%28+2.16+-1.08+%29+%2F+2.16+=+.5+
+1.08%2F2.16+=+.5+
+.5+=+.5+
OK