SOLUTION: A newspaper carrier has ​$5.80 in change. He has eight more quarters than dimes but four times as many nickels as quarters. How many coins of each type does he​ have?

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Question 987961: A newspaper carrier has ​$5.80 in change. He has eight more quarters than dimes but four times as many nickels as quarters. How many coins of each type does he​ have?
Answer by vleith(2983) About Me  (Show Source):
You can put this solution on YOUR website!
Let the number of dimes be d
You are told that the number of quarters is (d+8)
You are told the number of nickels is 4*quarters = 4*(d+8)
580+=+10%2Ad+%2B+5%2A%284%2A%28d%2B8%29%29+%2B+25%2A%28d%2B8%29
580+=+10d+%2B+5%2A%284d%2B32%29+%2B+25d%2B200
580+=+10d+%2B+20d+%2B+160+%2B+25d+%2B+200
580+-+160-200+=+10d%2B20d%2B25d
220+=+55d
220%2F55+=+d
4=d
there are 4 dimes
8+4 = 12 quarters
4*12=48 nickels