SOLUTION: How many pounds of candy worth $8 per lb should be mixed with 100 lb of candy worth $4 per lb to get a mixture that can be sold for $7 per lb?

Algebra ->  Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: How many pounds of candy worth $8 per lb should be mixed with 100 lb of candy worth $4 per lb to get a mixture that can be sold for $7 per lb?      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 987702: How many pounds of candy worth $8 per lb should be mixed with 100 lb of candy worth $4 per lb to get a mixture that can be sold for $7 per lb?
Answer by Edwin McCravy(20056) About Me  (Show Source):
You can put this solution on YOUR website!
How many pounds of candy worth $8 per lb should be mixed with 100 lb of candy
worth $4 per lb to get a mixture that can be sold for $7 per lb?
Let the number of lbs of the pricer candy we must add be x

Type       Number     Price    Value
 of          of       per        of
candy       lbs        lb      candy
-------------------------------------------
pricier      x         $8       $8x
cheaper    100         $4       $4(100)
-------------------------------------------
TOTALS    100+x        $7      $7(100+x)

 The equation comes from the column on the right

  %28matrix%284%2C1%2CValue%2Cof%2Cpricier%2Ccandy%29%29%22%22%2B%22%22%28matrix%284%2C1%2CValue%2Cof%2Ccheaper%2Ccandy%29%29%22%22=%22%22%28matrix%285%2C1%2CTotal%2Cvalue%2Cof%2CALL%2Ccandy%29%29

8x + 4(100) = 7(100+x)

Now you can finish.

Edwin