SOLUTION: A jet plane traveling at 500 mph overtakes a propeller plane traveling 150 mph that had a 5-hour head start. How far from the starting point are planes? The Planes are ? miles f

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Question 987632: A jet plane traveling at 500 mph overtakes a propeller plane traveling 150 mph that had a 5-hour head start. How far from the starting point are planes?
The Planes are ? miles from the starting point.
simplify your answer. Type an integer, fraction, or mixed number.

Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39630) About Me  (Show Source):
You can put this solution on YOUR website!
system%28R=500%2Cr=150%2Ch=5%2Ct=unknownTimeHours%2Cd=unknownDistance%29

Air Craft    speed    time     distance
Jet           R        t        d
Propellor     r       t+h       d

system%28Rt=d%2Cr%28t%2Bh%29=d%29
Solve this system to find a formula for the solution for d.

Answer by MathTherapy(10556) About Me  (Show Source):
You can put this solution on YOUR website!

A jet plane traveling at 500 mph overtakes a propeller plane traveling 150 mph that had a 5-hour head start. How far from the starting point are planes?
The Planes are ? miles from the starting point.
simplify your answer. Type an integer, fraction, or mixed number.
Let distance to the catch-up point (distance planes have traveled) be D
When the jet caught up with the propeller plane, both had traveled the same distance
Therefore, we get: D%2F500+=+D%2F150+-+5
3D = 10D - 7,500 -------- Multiplying by LCD, 1,500
3D - 10D = - 7,500
- 7D = - 7,500
D, or distance the catch-up point is from the starting point = %28-+7500%29%2F%28-+7%29, or highlight_green%281071%263%2F7%29 miles