Number 8: Number theory from Mixed Problem Solving
Find 2 numbers whose sum is 56 and whose product is 783.
What is asked in the problem?
Find 2 numbers whose sum is 56 and whose product is 783.
Representation:
Let x be the first number
y be the second number
Equation:
x + y = 56 (1st equation)
xy = 783 (2nd equation)
Solve the 2 equations, solve for x in terms of y using the first equation
x + y = 56
x = 56 - y
Substitute x to the second equation
xy = 783, where x = 56 - y
56 - y (y) = 783
56(y) - y(y) = 783
56y - y^2 = 783
0 = y^2 - 56y + 783
Factor the equation y^2 - 56y + 783 = 0 to find the value of y.
0 = y^2 - 56y + 783
0 = (y - 29)(y - 27)
0 = y - 29 0 = y - 27
y = 29 y = 27
There are 2 values for y. Substitute the values to either
of the two equations for find values of x.
x + y = 56, if y = 29
x + 29 = 56
x = 56 - 29
x = 27
x + y = 56, if y = 27
x + 27 = 56
x = 56 - 27
x = 29
Therefore if x = 29, y = 27.
if x = 27, y = 29.
There are two possibilities with the given problem.