Question 98758: A bunch trotted m miles at z miles per hour and arrived 3 hours late. How fast should they have trotted to have arrived on time? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! A bunch trotted m miles at z miles per hour and arrived 3 hours late. How fast should they have trotted to have arrived on time?
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Original parameters:
distance = m miles ; rate = z mph ; time = m/z hours
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New parameters to clip 3 hours off original time:
time = (m/z)-3 or (m-3z)/z hrs.
distance = m miles
rate = d/t = m/[(m-3z)/z]=[mz/(m-3z] mph
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Ans: They should have trotted at[mz/(m-3z] mph
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Cheers,
Stan H.
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