SOLUTION: The length of a rectangle is 50 centimeters longer than the width. If the perimeter of the rectangle is 220 centimeters, find the width and the length.

Algebra ->  Rectangles -> SOLUTION: The length of a rectangle is 50 centimeters longer than the width. If the perimeter of the rectangle is 220 centimeters, find the width and the length.      Log On


   

Question 987506: The length of a rectangle is 50 centimeters longer than the width. If the perimeter of the rectangle is 220 centimeters, find the width and the length.
Answer by algebrahouse.com(1659) About Me  (Show Source):
You can put this solution on YOUR website!
w = width
w + 50 = length {length is 50 longer than the width}

Perimeter of a rectangle = 2(width) + 2(length)

2w + 2(w + 50) = 220 {substituted width and length into perimeter formula}
2w + 2w + 100 = 220 {used distributive property}
4w + 100 = 220 {combined like terms}
4w = 120 {subtracted 100 from each side}
w = 30 {divided each side by 4}
w + 50 = 80 {substituted 30, in for w, into w + 50}

width = 30 cm
length = 80 cm

For more help from me, visit: www.algebrahouse.com