SOLUTION: what are the coordinates of the center of the ellipse graphed by the equation below? (x+14)^2/6^2+(y+17)^2/5^2=1?

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: what are the coordinates of the center of the ellipse graphed by the equation below? (x+14)^2/6^2+(y+17)^2/5^2=1?      Log On


   

Question 987347: what are the coordinates of the center of the ellipse graphed by the equation below? (x+14)^2/6^2+(y+17)^2/5^2=1?
Answer by macston(5194) About Me  (Show Source):
You can put this solution on YOUR website!
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For an ellipse:
%28x-h%29%5E2%2Fa%5E2%2B%28y-k%29%5E2%2Fb%5E2=1
In this form, (h,k) is the center.
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%28x%2B14%29%5E2%2F6%5E2%2B%28y%2B17%29%5E2%2F5%5E2=1
h=-14 and k=-17, so center is at (-14,-17)