SOLUTION: Three times the largest of three consecutive even integers exceeds twice the least 38

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Question 987213: Three times the largest of three consecutive even integers exceeds twice the least 38
Found 2 solutions by macston, stanbon:
Answer by macston(5194) About Me  (Show Source):
You can put this solution on YOUR website!
.
least integer=x; middle integer=x+2; largest integer=x+4
.
3(x+4)=2x+38
3x+12=2x+38
x=26
Least integer is x=26.
Middle integer is x+2=28.
Largest integer is x+4=30.

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Three times the largest of three consecutive even integers
exceeds twice the least by 38
-------
1st 2x-2
2nd 2x
3rd 2x+2
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Equation::
3(2x+2)-2(2x-2) = 38
6x + 6 - 4x + 4 = 38
-----
2x = 28
x = 14
------
1st: 28-2 = 26
2nd: 28
3rd: 30
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Cheers,
Stan H.
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