SOLUTION: arcsin(sin(-19pi/6))

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Question 987163: arcsin(sin(-19pi/6))
Answer by Edwin McCravy(20056) About Me  (Show Source):
You can put this solution on YOUR website!
arcsin%28sin%28-19pi%2F6%29%5E%22%22%29

Add 2pn to the angle.

arcsin%28sin%28-19pi%2F6%2B2pi%2An%29%5E%22%22%29

Set the angle between 0 and 2p 

0%3C=+-19pi%2F6%2B2pi%2An+%3C+2pi

Divide through by p

0%3C=-19%2F6%2B2n+%3C+2

Multiply through by 6

0%3C=-19%2B12n+%3C+12

Add 19 to both sides

19%3C=12n+%3C+31

Divide through by 12

1.583%3C=n%3C2.583

So n = 2

arcsin%28sin%28-19pi%2F6%2B2pi%2A2%29%5E%22%22%29

arcsin%28sin%28-19pi%2F6%2B4pi%29%5E%22%22%29

arcsin%28sin%28-19pi%2F6%2B24pi%2F6%29%5E%22%22%29

arcsin%28sin%285pi%2F6%29%5E%22%22%29

arcsin%281%2F2%29

pi%2F6

Edwin