SOLUTION: Calculate the turning point of the quadratic function y=4x^2-7x+3

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Question 987157: Calculate the turning point of the quadratic function
y=4x^2-7x+3
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Using the derivative:
dy%2Fdx=8x-7
Set the derivative equal to zero.
8x-7=0
8x=7
x=7%2F8
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.
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Using the vertex form:
Convert to vertex form,
y=4%28x%5E2-%287%2F4%29x%29%2B3
y=4%28x%5E2-%287%2F4%29x%2B%287%2F8%29%5E2%29%2B3-4%287%2F8%29%5E2
y=4%28x-7%2F8%29%5E2%2B3-4%2849%2F64%29
y=4%28x-7%2F8%29%5E2%2B48%2F16-49%2F16
y=4%28x-7%2F8%29%5E2-1%2F16
Vertex is (7%2F8,-1%2F16)