SOLUTION: How would you "remove the discontinuity" of f ? In other words, how would you define f(3) in order to make f continuous at 3? f(x) = (x^2 − x − 6)/(x −

Algebra ->  Test -> SOLUTION: How would you "remove the discontinuity" of f ? In other words, how would you define f(3) in order to make f continuous at 3? f(x) = (x^2 − x − 6)/(x −       Log On


   

Question 987096: How would you "remove the discontinuity" of f ? In other words, how would you define f(3) in order to make f continuous at 3?
f(x) = (x^2 − x − 6)/(x − 3)
Answer by ikleyn(52794) About Me  (Show Source):
You can put this solution on YOUR website!
.
f%28x%29 = %28x%5E2+-+x+-+6%29%2F%28x+-+3%29 =           -----> (factorize the numerator) ----->

= %28%28x%2B2%29%2A%28x-3%29%29%2F%28x-3%29 = x+%2B+2.

At  x=3  you  have   x+2 = 5.

So,  define   f(3) = 5,  and you will have the continuous function.