Question 986896: a. Find two consecutive even integers such that twice the smaller exceeds the larger by 18.
b. The sum of two numbers is 18. The larger number exceeds the smaller by 4.
Please answer this two questions immediately because I need it now. Thank you so much :)
Answer by josgarithmetic(39630)   (Show Source):
You can put this solution on YOUR website! Let x b any integer.
2x will be an even integer.
2x and 2x+2 are two consecutive even integers. Alternatively, 2x-2 and 2x are two consecutive even integers.
Let x and y be two real numbers.
If their sum is 18, then x+y=18;
if their difference is 4, and if y>x, then y-x=4.
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