SOLUTION: The dimensions of a rectangle are such that it's length is 7in more than its width. If the length were doubled and if the width were decreased by 3 in, the area would be increased

Algebra ->  Rectangles -> SOLUTION: The dimensions of a rectangle are such that it's length is 7in more than its width. If the length were doubled and if the width were decreased by 3 in, the area would be increased       Log On


   

Question 986809: The dimensions of a rectangle are such that it's length is 7in more than its width. If the length were doubled and if the width were decreased by 3 in, the area would be increased by 168 in^2. What are the length and width of the rectangle?
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
w and L for original dimensions;
L=7%2Bw, given;
A=wL=w%28w%2B7%29

Changed dimensions;
2L=2%28w%2BL%29 for length;
-
w-3 for width;
2L%28w-3%29-wL=168, should make sense.
Work with this and find w and L.