SOLUTION: Determine the gradient of the tangent to the following curve where x=2: y=(x^2 -3)(x+3)

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Question 986687: Determine the gradient of the tangent to the following curve where x=2: y=(x^2 -3)(x+3)
Answer by Cromlix(4381) About Me  (Show Source):
You can put this solution on YOUR website!
Hi there,
y = (x^2 - 3)(x + 3)
y = x^3 + 3x^2 - 3x - 9
Differentiate:
dy/dx = 3x^2 + 6x - 3
Substitute x = 2
= 3(2)^2 + 6(2) - 3
= 12 + 12 - 3
= 21
Gradient of tangent = 21
Hope this helps :-)