SOLUTION: the second side of a triangular deck is 5 feet longer than the shortest side and a third side is 5 feet short than twice the length of the shortest side. if the perimeter is 52 ft

Algebra ->  Triangles -> SOLUTION: the second side of a triangular deck is 5 feet longer than the shortest side and a third side is 5 feet short than twice the length of the shortest side. if the perimeter is 52 ft       Log On


   

Question 986670: the second side of a triangular deck is 5 feet longer than the shortest side and a third side is 5 feet short than twice the length of the shortest side. if the perimeter is 52 ft what are the lengths of the three sides.
Found 2 solutions by Cromlix, solver91311:
Answer by Cromlix(4381) About Me  (Show Source):
You can put this solution on YOUR website!
Hi there,
Shortest side = 'x'
Second side = x + 5
Third side = 2x - 5
Perimeter = Three sides added together
52 ft = x + (x + 5) + (2x - 5)
52 ft = x + x + 5 + 2x - 5
Collect like terms
4x = 52 ft
x = 13 ft
Shortest side = 13 ft.
Second side = 18 ft.
Third side = 21 ft
Hope this helps :-)

Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


is the short side, is the second side. is the long side.



Solve for , then calculate and

John

My calculator said it, I believe it, that settles it