SOLUTION: Mike and Adam left a bus terminal at the same time and traveled in opposite directions. Mikes bus was in heavy traffic and had to travel 20 mi/h slower than Adams bus. After 3 hour
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Question 986605: Mike and Adam left a bus terminal at the same time and traveled in opposite directions. Mikes bus was in heavy traffic and had to travel 20 mi/h slower than Adams bus. After 3 hours, their buses were 270 miles apart. How fast was each bus going
Now my question is how do I set up the equation to be able to solve it Answer by josmiceli(19441) (Show Source):
You can put this solution on YOUR website! Let = the speed of Adam's bus = the speed of Mike's bus
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The best way to solve this is to think of one
of the buses standing still and the other one
traveling at the sum of their speeds.
It doesn't matter which one is standing still
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and
The speed of Adam's bus is 55 mi/hr
The speed of Mike's bus is 35 mi/hr
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check: mi
and mi
------------------- mi
OK
