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Question 98656: Please I could really use your help. I'm lost. Here is the question.
Write an equation of a line in standard form given these two points.
(2/3,-1/4) and (5/9, -13/15). I am so confused. This question is from
my teacher.
Answer by malakumar_kos@yahoo.com(315)   (Show Source):
You can put this solution on YOUR website!
Write an equation of a line in standard form given these two points.
(2/3,-1/4) and (5/9, -13/15)
( x1,y1) = (2/3,-1/4) (x2,y2) = (5/9,-13/15)
x2-x1/x-x1 = y2-y1/y-y1
(5/9-2/3)/(x-2/3) = (-13/15+1/4)/(y+1/4)
( 15-2/9)/(3x-2)/3 = [(-52+15)/60]/4y+1/4
13(3)/9(3x-2) = -37/60/4y+1/4
13/3(3x-2) = -37(4)/60(4y+1)
13/3(3x-2) = -37/15(4y+1)
13 .5(4y+1) = -37(3x-2)
65(4y+1) = -111x+74
111x + 260y+65-74 = 0
111x +260y -9 = 0 is the required eq'n
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