SOLUTION: Peter can do a whole job in half the time it takes Henry to do it. Together they can finish the job in 10 days. How many days will it take Peter to do the job alone?

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Question 986460: Peter can do a whole job in half the time it takes Henry to do it. Together they can finish the job in 10 days. How many days will it take Peter to do the job alone?

Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39621) About Me  (Show Source):
You can put this solution on YOUR website!

PERSON   RATE
Peter    2/x
Henry    1/x
Joint    1/10


Find Henry's rate first unless you want to take the unknown times from another viewpoint.

Note that x is not a rate; it is the time for Henry to do one whole job himself.

2%2Fx%2B1%2Fx=1%2F10
-
-
3%2Fx=1%2F10
x%2F3=10
x=30-----time in days for Henry to do one job alone.

The practical sense is that Peter is twice as fast as Henry, so Peter can do the same one job alone in 15 days.

Answer by MathTherapy(10555) About Me  (Show Source):
You can put this solution on YOUR website!

Peter can do a whole job in half the time it takes Henry to do it. Together they can finish the job in 10 days. How many days will it take Peter to do the job alone?
Let time Peter takes be P
Then Henry can do job in 2P days
Peter can do 1%2FP of job in 1 day, and Henry can do 1%2F%282P%29 of job in 1 day
Together they can do: 1%2FP+%2B+1%2F%282P%29+=+1%2F10
10 + 5 = P -------- Multiplying by LCD, 10P
P, or time Peter takes = highlight_green%2815%29 days