SOLUTION: Let f (x) = 1/x + 3 and g(x) = 3x/x + 3 Find f + g, f − g, f g, f/g and their domains. NOTE: Enter DNE in any unused blanks. (f + g)/(x) = Domain: (&#8

Algebra ->  Inequalities -> SOLUTION: Let f (x) = 1/x + 3 and g(x) = 3x/x + 3 Find f + g, f − g, f g, f/g and their domains. NOTE: Enter DNE in any unused blanks. (f + g)/(x) = Domain: (&#8      Log On


   



Question 986421: Let f (x) = 1/x + 3
and g(x) = 3x/x + 3

Find f + g, f − g, f g, f/g and their domains.
NOTE: Enter DNE in any unused blanks.
(f + g)/(x) =
Domain:
(−∞, a] ∪ [b, ∞)

(−∞, a) ∪ (a, ∞)

(−∞, ∞)

(−∞, a) ∪ (b, ∞)

(−∞, a) ∪ (a, b) ∪ (b, ∞)
a =
b =



(f − g)/(x) =
Domain:
(−∞, a) ∪ (b, ∞)

(−∞, a) ∪ (a, b) ∪ (b, ∞)

(−∞, a] ∪ [b, ∞)

(−∞, ∞)

(−∞, a) ∪ (a, ∞)
a =
b =





(fg)/(x) =
Domain:
(−∞, a) ∪ (b, ∞)

(−∞, a) ∪ (a, b) ∪ (b, ∞)

(−∞, a] ∪ [b, ∞)

(−∞, ∞)

(−∞, a) ∪ (a, ∞)
a =
b =





f/g(x) =

(Don't forget to simplify)
Domain: [Remember to find the domain before simplifying the function.]
(−∞, a) ∪ (a, b) ∪ (b, ∞)

(−∞, a] ∪ [b, ∞)

(−∞, a) ∪ (b, ∞)

(−∞, a) ∪ (a, ∞)

(−∞, ∞)
a =
b =

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
f%2Bg=%281%2B3x%29%2F%28x%2B3%29
All numbers except x=-3
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.
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f-g=%281-3x%29%2F%28x%2B3%29
All numbers except x=-3
.
.
.
f%2Ag=%283x%29%2F%28x%2B3%29%5E2
All numbers except x=-3
.
.
.
f%2Fg=%281%2F%28x%2B3%29%29%28%28x%2B3%29%2F3x%29=1%2F%283x%29
All numbers except x=0 and x=-3