SOLUTION: log2 (x+y)=3 and x2-3y2=4, solve the above equation

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Question 986306: log2 (x+y)=3 and x2-3y2=4, solve the above equation
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
log2 (x+y)=3
x2-3y2=4
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log%282%2C%28x%2By%29%29+=+3 --> x+y = 8
y = 8-x
Sub for y in the 2nd equation.
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Use ^ (Shift 6) for exponents.
x^2 - 3y^2 = 4
x%5E2+-+3%288-x%29%5E2+=+4