SOLUTION: The length of a new rectangular playing field is 3 yards longer than quadruple the width. If the perimeter of the rectangular is 526 yards what are the dimensions?
Algebra ->
Equations
-> SOLUTION: The length of a new rectangular playing field is 3 yards longer than quadruple the width. If the perimeter of the rectangular is 526 yards what are the dimensions?
Log On
Question 986270: The length of a new rectangular playing field is 3 yards longer than quadruple the width. If the perimeter of the rectangular is 526 yards what are the dimensions? Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! let width be w
length I = 3+4w
perimeter = 2(w+(3+4w))=526
2w+6+8w=526
10w=526-6
10w=520
w=52
plug and find l
3+4*52
3+208
=211
