SOLUTION: What is the coefficient of {{{x^3y^4}}} in the binomial expansion of {{{(x+y)^7}}}? Thank you kindly.

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Question 986242: What is the coefficient of x%5E3y%5E4 in the binomial expansion of %28x%2By%29%5E7?
Thank you kindly.

Answer by MathTherapy(10549) About Me  (Show Source):
You can put this solution on YOUR website!
What is the coefficient of x%5E3y%5E4 in the binomial expansion of %28x%2By%29%5E7?
Thank you kindly.
For this problem, the formula to determine a specific term in a Bernoulli/Binomial expansion should be used. It states:
%28a+%2B+b%29%5En+=%22+%22%5Bn%5DC%5Br+-+1%5D%28a%29%5E%28n-%28r-1%29%29%28b%29%5E%28r-1%29, where r = term number
We have: %28x+%2B+y%29%5E7, which becomes: %28x+%2B+y%29%5E7+=%22+%22%5B7%5DC%5Br+-+1%5D%28x%29%5E%287-%28r-1%29%29%28y%29%5E%28r-1%29
The expression: x%5E3y%5E4, without its coefficient, occurs at the term where x%5E3y%5E4+=+%28x%29%5E%287+-+%28r+-+1%29%29y%5E%28r+-+1%29
Thus, 3 = 7 - (r - 1)
3 = 7 - r + 1
3 = 8 - r
3 - 8 = - r
- 5 = - r
r, or term number where x%5E3 occurs = %28-+5%29%2F%28-+1%29, or 5
Confirming this, and as seen above, y%5E4 occurs at y%5E%28r+-+1%29, and so:
4 = r - 1
4 + 1 = r
r, or term number where y%5E4 occurs = 5
This means that the expression: x%5E3y%5E4 without its coefficient occurs at the 5th term
We now have: %22+%22%5B7%5DC%5Br+-+1%5D%28x%29%5E%287-%28r-1%29%29%28y%29%5E%28r-1%29, with r or term number being 5
This becomes: %22+%22%5B7%5DC%5B5-1%5D%28x%29%5E%287-%285-1%29%29%28y%29%5E%285-1%29
%22+%22%5B7%5DC%5B4%5D%28x%29%5E%287-4%29%28y%29%5E%285-1%29
35x%5E3y%5E4
As seen the coefficient of x%5E3y%5E4 in the expansion of: %28x+%2B+y%29%5E7 is: highlight_green%2835%29