Question 986161: Find the values of a, b, and c such that the equation y = ax2 + bx + c has ordered pair solutions (-1, -4), (2, -7) and (3, 0)
this is just a pretest
Found 3 solutions by stanbon, solver91311, MathLover1:
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Find the values of a, b, and c such that the equation y = ax2 + bx + c has ordered pair solutions (-1, -4), (2, -7) and (3, 0)
this is just a pretest
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Form:: ax^2 + bx + c = y
Solve for a,b, and c using the 3 pairs::
a - b + c = -4
4a +2b + c = -7
9a +3b + c = 0
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Using any method you know solve for a, b, and c::
Ans::
a = 2 ; b = -3 ; c = -9
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Equation:
y = 2x^2 -3x - 9
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Cheers,
Stan H.
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Answer by solver91311(24713)  (Show Source):
Answer by MathLover1(20850)  (Show Source):
You can put this solution on YOUR website! Find the values of  ,  , and  such that the equation  has ordered pair solutions ( , ), ( , ) and ( , ):
for ( , )=(,)
 .............eq.1
for (,)= (,)
 .............eq.2
for (,)=(,)
 .............eq.3
solve this system:
.............eq.1
.............eq.2
.............eq.3
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start with
.............eq.1
.............eq.2...subtract 1 from 2
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 .............eq.1a
go with
.............eq.2
.............eq.3..........subtract 2 from 3
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 ..........eq.2a
from eq.1a and 2a we have
 ........solve for
go to
 .............eq.1a.....substitute for
go to .............eq.3 ...substitute for , for
so, your equation is: 
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