SOLUTION: Jane has $776 in ten-dollar, five-dollar, and one-dollar bills. There are 135 bills in all. There are 25 more ten-dollar bills than five-dollar bills. How many bills of each kind d
Question 986131: Jane has $776 in ten-dollar, five-dollar, and one-dollar bills. There are 135 bills in all. There are 25 more ten-dollar bills than five-dollar bills. How many bills of each kind does Jane have?
(Enter the number of bills as an ordered triple.)
Thank you kindly. Answer by srinivas.g(540) (Show Source):
You can put this solution on YOUR website! let x be no of ten dollar bills
let y be no of five dollar bills
let z be no of one dollar bills
x+y+z = 135
x=25+y
put x=25+y in above equation
25+y+y+z=135
25+2y+z=135
2y+z=110...........eq(1)
sum = $776
x*10+y*5+z=776
put x=25+y in the above equation
(25+y)*10+5y+z=776
250+10y+5y+z=776
15y+z=776-250
15y+z=526........eq(2)
solve equation 1 and 2
subtract eq 1 from eq 2
15y+z-(2y+z)=526-110
13y =416
y= 416/13
y=32
x= 25+32
= 57
but x+y+z=135
57+32+z=135
89+z=135
z=46
no of on ten dollar bills (x)=57
no of on five dollar bills (y)=32
no of one dollar bills (z)=46
