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Question 98607: m+ax^2+bx+c for b
I have no idea how to do this please help me!
Answer by checkley71(8403)   (Show Source):
You can put this solution on YOUR website! FIRST YOU MUST ISOLATE B ON THE LEFT SIDE OF THE EQUATION THUS:
M+AX^2+BX+C=0
BX=-M-AX^2-C NOW DIVIDE BOTH SIDES OF THE EQUATION BY X TO ISOLATE THE B TERM THUS:
B=(-M-AX^2-C)/X ANSWER.
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IF YOUR PROBLEM IS M=AX^2+BX+C THEN:
BX=M-AX^2-C
X=(M-AX^2-C)/X
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