SOLUTION: i^3(4i^2+i) f(x)=9(.7+.2)^x
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Question 985984
:
i^3(4i^2+i)
f(x)=9(.7+.2)^x
Answer by
Alan3354(69443)
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i^3(4i^2+i)
= -i*(-4 + i)
= -i^2 + 4i
= 1 + 4i
----------------------
f(x)=9(.7+.2)^x
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