SOLUTION: Jasmine and her friends eat half a bag of lollies on her birthday. The next day they eat three quarters of the number they ate the day before. Then there are 8 lollies left. How

Algebra ->  Human-and-algebraic-language -> SOLUTION: Jasmine and her friends eat half a bag of lollies on her birthday. The next day they eat three quarters of the number they ate the day before. Then there are 8 lollies left. How      Log On


   



Question 985982: Jasmine and her friends eat half a bag of lollies on her birthday. The next day they eat three quarters of the number they ate the day before. Then there are 8 lollies left. How many were in the bag to begin with?
Answer by Edwin McCravy(20065) About Me  (Show Source):
You can put this solution on YOUR website!
Jasmine and her friends eat half a bag of lollies on her birthday. The next day
they eat three quarters of the number they ate the day before. Then there are 8
lollies left. How many were in the bag to begin with?
There are two ways to do it, with and without algebra. I'll do it both ways:

FIRST WAY (WITHOUT ALGEBRA):

Start at the end and go backwards.

There were 8 lollies left. 

Therefore since 8 were left after taking three quarters, the 8 must have been
the one quarter that was left, so there were 4 times 8 or 32 lollies before.

Then before that they ate half a bag, so those 32 must have been half of what
they started with, so they started with 64 lollies.

SECOND WAY (WITH ALGEBRA)

There were N lollies to begin with 

Jasmine and her friends eat half a bag of lollies on her birthday.
So there was half a bag or expr%281%2F2%29N left

The next day they eat three quarters of the number they ate the day before.
Since they ate expr%281%2F2%29N the day before, they ate expr%283%2F4%29%2Aexpr%281%2F2%29N, so we subtract that from what they had left.
So after that, the had this many left:

expr%281%2F2%29N%22%22-%22%22expr%283%2F4%29%2Aexpr%281%2F2%29N  

Multiplying those two fractions

expr%281%2F2%29N-expr%283%2F8%29N 

Then there are 8 lollies left.
So we set that equal to 8

expr%281%2F2%29N-expr%283%2F8%29N%22%22=%22%228

Multiply through by LCD = 8

4N-3N=64

N=64

Same answer as when we didn't use algebra and worked backwards.

Edwin