Jasmine and her friends eat half a bag of lollies on her birthday. The next day
they eat three quarters of the number they ate the day before. Then there are 8
lollies left. How many were in the bag to begin with?
There are two ways to do it, with and without algebra. I'll do it both ways:
FIRST WAY (WITHOUT ALGEBRA):
Start at the end and go backwards.
There were 8 lollies left.
Therefore since 8 were left after taking three quarters, the 8 must have been
the one quarter that was left, so there were 4 times 8 or 32 lollies before.
Then before that they ate half a bag, so those 32 must have been half of what
they started with, so they started with 64 lollies.
SECOND WAY (WITH ALGEBRA)
There were N lollies to begin with
Jasmine and her friends eat half a bag of lollies on her birthday.
So there was half a bag or
left
The next day they eat three quarters of the number they ate the day before.
Since they ate
the day before, they ate
, so we subtract that from what they had left.
So after that, the had this many left:


Multiplying those two fractions
Then there are 8 lollies left.
So we set that equal to 8


Multiply through by LCD = 8
Same answer as when we didn't use algebra and worked backwards.
Edwin