SOLUTION: 1)If sinA=sinB and cosA=cosB then A=______. 2)If (1+tan x)(1+tan y)=2 then x+y=_____. 3)If tanx+tan(60°+x)+tan(120°+x)=3 then x=______. 4)1+ sinx +sin^2x..........=4

Algebra ->  Trigonometry-basics -> SOLUTION: 1)If sinA=sinB and cosA=cosB then A=______. 2)If (1+tan x)(1+tan y)=2 then x+y=_____. 3)If tanx+tan(60°+x)+tan(120°+x)=3 then x=______. 4)1+ sinx +sin^2x..........=4      Log On


   



Question 985872: 1)If sinA=sinB and cosA=cosB then A=______.



2)If (1+tan x)(1+tan y)=2 then x+y=_____.
3)If tanx+tan(60°+x)+tan(120°+x)=3 then x=______.
4)1+ sinx +sin^2x..........=4+2√3,0 5)The values if x in (-Π,Π) which satisfy the equation 8^(1+|cos x|+|cos^2x|+|cos^3x|+........).


Answer by Edwin McCravy(20056) About Me  (Show Source):
You can put this solution on YOUR website!
1)If sinA=sinB and cosA=cosB then A=B or else they differ by 2pi or 360%B0
 

Since the period of sine and cosine is 2pi or 360°, the general solution is 
A=B%2B2pi%2An or A = B + 360°n, where n is any integer   

2)If 
%281%2Btan%28x%29%5E%22%22%29%281%2Btan%28y%29%5E%22%22%29%22%22=%22%222 then x%2By%22%22=%22%22_____.

FOIL out the left side:
1+%2B+tan%28x%29+%2B+tan%28y%29+%2B+tan%28x%29tan%28y%29%22%22=%22%222
If we remember our identities and also notice that we are 
asked to find x+y, and notice that there are tangents in
the problem and then we we think of the identity we 
have memorized for tan(x+y)
tan%28x%2By%29%22%22=%22%22%28tan%28x%29%2Btan%28y%29%29%2F%281-tan%28x%29tan%28y%29%29
We recognize some of the terms in our equation are like some
of the terms in that identity so let's get tan(x)+tan(y) alone
on the left side since that's the numerator of the right side
of that identity:
1+%2B+tan%28x%29+%2B+tan%28y%29+%2B+tan%28x%29tan%28y%29%22%22=%22%222

tan%28x%29+%2B+tan%28y%29%22%22=%22%221-tan%28x%29tan%28y%29

Well what do you know! the right side is just the denominator 
of the right side of that identity: 
So we divide both sides by the right side:    
%28tan%28x%29+%2B+tan%28y%29%29%2F%281-tan%28x%29tan%28y%29%29%22%22=%22%22%281+-+tan%28x%29tan%28y%29%29%2F%281-tan%28x%29tan%28y%29%29 
  
The left side is the left side of that identity and the right side is 1. 
So we have

tan%28x%2By%29%22%22=%22%221
Since the period of the tangent is pi or 180°
x+y = pi%2F4%2Bpi%2An or 45°+180°n, where n is any integer, positive,
negative, or zero. 

Limit: 2 problems

Edwin