SOLUTION: Let Ө be an angle in Quadrant II such that cosӨ=-4/9.
Find the exact values of cscӨ and cotθ.
(not sure if it posted or not, because my browser closed
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-> SOLUTION: Let Ө be an angle in Quadrant II such that cosӨ=-4/9.
Find the exact values of cscӨ and cotθ.
(not sure if it posted or not, because my browser closed
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Question 985796: Let Ө be an angle in Quadrant II such that cosӨ=-4/9.
Find the exact values of cscӨ and cotθ.
(not sure if it posted or not, because my browser closed as soon as I tried to post it [sorry if this question is doubled] but it would be greatly appreciated. Thank you!) :/ Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Let Ө be an angle in Quadrant II such that cosӨ=-4/9.
Find the exact values of cscӨ and cotθ.
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By definition, csc = r/y and cot = y/x
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Since cos = x/r, x = -4 and r = 9 in QII
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Then y = sqrt[9^2-4^2] = sqrt(65)
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Ans:
csc = r/y = 9/sqrt(65)
cot = y/x = -sqrt(65)/9
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Cheers,
Stan H.
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