SOLUTION: Let Ө be an angle in Quadrant II such that cosӨ=-4/9. Find the exact values of cscӨ and cotθ.

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Question 985793: Let Ө be an angle in Quadrant II such that cosӨ=-4/9.
Find the exact values of cscӨ and cotθ.
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Let Ө be an angle in Quadrant II such that cosӨ=-4/9.
Find the exact values of cscӨ and cotθ.
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Use (-4,9) as the terminal point.
r is the distance from the Origin.
r+=+sqrt%284%5E2+%2B+9%5E2%29+=+sqrt%2897%29
csc = 1/sin = r/y
cot = x/y